3[2x+11]=6x+33

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Solution for 3[2x+11]=6x+33 equation:


Simplifying
3[2x + 11] = 6x + 33

Reorder the terms:
3[11 + 2x] = 6x + 33
[11 * 3 + 2x * 3] = 6x + 33
[33 + 6x] = 6x + 33

Reorder the terms:
33 + 6x = 33 + 6x

Add '-33' to each side of the equation.
33 + -33 + 6x = 33 + -33 + 6x

Combine like terms: 33 + -33 = 0
0 + 6x = 33 + -33 + 6x
6x = 33 + -33 + 6x

Combine like terms: 33 + -33 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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